Question

a swimming pool can be filled by two pipes A and B in 9 3/5 hrs. If pipe A alone takes 16 hrs to fill the pool, in how much time will the pool be filled if pipe B alone is open.

Answer 1

Solution:

Given: The swimming pool,when filled by 2 pipes (A and B) takes 9 3/5 hours.
A alone fills the pool in 16 hours.

Let the volume of the swimming pool be v, and the time taken by pipe B alone to fill th tank be x,
then,the ability of pipe A to fill the tank in 1 hour equals V/16,
then,the ability of pipe B to fill the tank in 1 hour equals V/x

   V/16+V/x =V/(9 3/5)
V(1/16+1/x)=V[1/(48/5)]
   1/16 + 1/x = 5/48
    x+16/16x = 5/48
    (x+16)48  = (5)(16x)
    48x+768  = 80x
            768   = 80x-48x
             32x=768
                 x= 24....2nd pipe takes 24 hours(1 full day) to fill the tank

Answer 2

Answer:

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