Question

a swimming pool is 20 m in length, 15 m in breadth, 4 m in depth. Find the cost of cementing it's floor and walls at rupees 35 per m sq​

Answer 1

Answer:

First find the lsa + lb ....

.lsa 2h<l+b>

2*4<20+15>

8*35

280

now lb....

20*15

300

add them

280+300

580

now cost is 12 per m sq so

....580*12

6960 rupee

hope it will help you

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Answer 2

Given:

• Length = 20 m
• Breadth = 15 m
• Height = 4 m
• Rate = ₹ 35 per m

To find:

• The cost of cementing its floor and walls at rupees 35 per m²

Solution:

$\begin{gathered} : \implies\sf Area_{\:(cemented)} = TSA - Area_{\;(top)}\\\\\\\end{gathered} \\ \begin{gathered} : \implies\sf\quad 2\Big\{L \times B \Big\} + \Big\{B \times H \Big\} + \Big\{H \times L\Big\} - \Big\{L \times B\Big\}\\\\\\\end{gathered} \\ \\\begin{gathered} : \implies\sf\quad 2\Big\{20 \times 15\Big\} + \Big\{15\times4\Big\} + \Big\{4 \times 20\Big\} - \Big\{20 \times 15\Big\}\\\\\\\end{gathered} \\ \\ \begin{gathered} : \implies\sf\quad 2\Big\{300 + 60 + 80\Big\} - 300\\\\\\\end{gathered} \\ \\ \\ \begin{gathered} :\implies\sf\quad2\times 440 - 300\\\\\\\end{gathered} \\ \\ \begin{gathered} : \implies\sf\quad 880 - 300\\\\\\\end{gathered} \\ \\ \begin{gathered} : \implies\quad\underline{\boxed{{\frak{580\;m^2}}}} \pink\bigstar\\\end{gathered} \\ \\ \\ \begin{gathered}\rule{230px}{.2ex}\\\end{gathered}$

Cost of Cementing:

$\begin{gathered} \boxed{\boxed{ \frak{ \color{navy}{Cost = (Given \: rate \: × Area \: of \: the \: Pool) }}}} \\ \mapsto \sf{⠀Cost = 35 × 580} \\ \mapsto \sf⠀Cost = ₹ 20,300 \end{gathered}$$\underline{ \sf \: Hence, \: the \: cost \: of \: cementing \: will \: be {\textbf{ \textsf{ ₹20,300}}}.}$

Thank you!!

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