Math, asked by gurpreetsingh2001gil, 6 months ago

A swimming pool is 20m long 15m wide and 5m deep . find the cost of repairing the floor and wall at the rate of rs25per square metre​

Answers

Answered by asaduddinmahmood795
0

Answer:

Step-by-step explanation:

Given that

Length= 20m

Breadth=15m

5m deep

CSA of swimming pool

2h(l+b)

2*5(20+15)

10(35)

350 Sq.m

Area of floor

lxb

20x15

300

Total Sq.m= 350+300

650 Sq.m

Cost of repairing per Sq.m is 25 rupees

Therefore

650x25

16,250 rupees

Answered by dunukrish
0

Answer:

Step-by-step explanation:

The length of the swimming pool=20 m

Width=15 m

Depth=5 m

So,area ofthe floor=l×b=20×15

=300 sq.m

Area of the four walls

=2×h(l+b)

=2×5(20+15)

=10×35=350 sq.m

Therefore total area to be repaired

300+350=650 sq.m

Cost of repairs=₹25/sq.m

So total cost=650×25=₹16250.(Answer)

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