Math, asked by obiorahpaul3, 10 months ago

A swimming pool is 20meters wide and has a diagonal length of 52meters. How much shorter is it than a 50meters pool?

Answers

Answered by RvChaudharY50
1

Answer:

2m

Step-by-step explanation:

Length of swimming pool = (52)²-(20)² = (52+20)(52-20) = 72*32 = 2304 = 48m

shorter than 50m pool = 2m (Ans.)

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Answered by venupillai
2

Answer:

The given pool is 2m shorter than a 50m pool

Step-by-step explanation:

The given swimming pool is 20m wide and has a diagonal length of 52m. This represents a right-angled triangle. Let the length of the pool be L. Using Phythagoras theorem, we get:

52^2 = 20^2 + L^2

L^2 = 2704 - 400

      = 2304

L = √2304

L = 48m

The longer side of the pool is 48m, which is 2m shorter than a 50m pool.

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