Question

a swimming pool is 21m long, 14m wide, and 6m deep. find the sum of the area of the four walls and its floor.​

Answer 1

Given :-

• Length of the swimming pool = 21 m
• Breadth of the swimming pool = 14 m
• Height of the swimming pool = 6 m

To find :-

• Sum of area of the four walls and it's floor

Knowledge required :-

→ Formula to calculate area of cuboid :-

Area of cuboid = 2(lb + bh + hl)

where,

• l = length of the cuboid
• b = breadth of the cuboid
• h = height of the cuboid

Solution :-

⠀⠀⠀⇒ Area = 2(lb + bh + hl)

⠀⠀⠀⇒ Area = 2(21 × 14 + 14 × 6 + 6 × 21)

⠀⠀⠀⇒ Area = 2(294 + 84 + 126)

⠀⠀⠀⇒ Area = 2(504)

⠀⠀⠀⇒ Area = 1008

Sum of area of the four walls and it's floor = 1008 m²

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Know MorE :-

• Volume of cuboid =  length × breadth × height
• Perimeter of cuboid = 4 (length + breadth + height)
• Total surface area of cube = 6 × side²
• Volume of cube = side³
• Perimeter of cube = 12 × side

Answer 2

★ Given :

• Length of pool = 21m
• Breadth of pool = 14m
• Height of pool = 6m

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★ To find :

• Total surface area of pool.

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★Solution :

↪ T.S.A of cuboid = 2 (lb + bh + hl)

➯ T.S.A of pool = 2 [( 21 × 14 ) + (14×6) + (6×21)]

➯ T.S.A = 2 { 294 + 84 + 126 }

➯ T.S.A = 2 {504}

➯ T.S.A = 1008 m²

➠ Therefore, Total surface area of pool = 1008 m²

Explore more :-

↝ Lateral surface area of cuboid = 2(l + b)h

↝Volume of cuboid = l × b × h

↝ T.S.A of cube = 6(side)²

↝ Lateral surface area of cube = 4 (side)²

↝ Volume of cube = side³

↝ Area of recatangle = l × b

↝ Area of square = side ²

↝area of triangle = ½ × base × height

↝ perimeter of triangle = sum of all sides