Math, asked by sanjaykumarkuma4536, 1 year ago

A swimming pool is 24 m long and 15 m broad, when a number of men dive into the pool, the height of the water rises by 1 cm. If the average amount of water displaced by one of the men be 0.1 cu. m, how many men are there in the pool?

Answers

Answered by Help4U
48

so here is the answer

volume raised after dive of few men

= 24*15*0.01=3.6 cu.m

as each men rise the volume by 0.1 cu.m,

no. of men = 3.6/0.1 = 36

thus, 36 men dived into the pool.

plz mark as brainliestvolume raised after dive of few men

= 24*15*0.01=3.6 cu.m

as each men rise the volume by 0.1 cu.m,

no. of men = 3.6/0.1 = 36

thus, 36 men dived into the pool.

Answered by parambrata777A
5

Step-by-step explanation:

let the no of men be n.

BTP

n×0•1=24×15×1/100

or n=24×15×1/100×10

=36

Therefore 36 men dive into the pool

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