A swimming pool is 24 m long and 15 m broad, when a number of men dive into the pool, the height of the water rises by 1 cm. If the average amount of water displaced by one of the men be 0.1 cu. m, how many men are there in the pool?
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Answered by
48
so here is the answer
volume raised after dive of few men
= 24*15*0.01=3.6 cu.m
as each men rise the volume by 0.1 cu.m,
no. of men = 3.6/0.1 = 36
thus, 36 men dived into the pool.
plz mark as brainliestvolume raised after dive of few men
= 24*15*0.01=3.6 cu.m
as each men rise the volume by 0.1 cu.m,
no. of men = 3.6/0.1 = 36
thus, 36 men dived into the pool.
Answered by
5
Step-by-step explanation:
let the no of men be n.
BTP
n×0•1=24×15×1/100
or n=24×15×1/100×10
=36
Therefore 36 men dive into the pool
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