Question

A swimming pool is filled with three taps with uniform flow of water. The first two taps fill pool in the same time during which the pool is filled by the third tap alone . The second tap fills the pool 5hrs faster than the first tap and 4hrs slower than the third tap. Find the time required by each tap to fill the pool separately plz plz plz help me plz

Answer 1

Answer:

Let V be the volume of the pool and x the number of hours required by the second pipe alone to fill the pool. Then, the first pipe takes (x+5) hours, while the third pipe takes (x−4) hours to fill the pool. So, the parts of the pool filled by the first, second and third pipes in one hour are respectively

x+5V,xV,x−4V

Let the time taken by the first and second pipes to fill the pool simultaneously be t hours.

Then, the third pipe also takes the same time to fill the pool

∴(x+5V+xV)t= Volume of the pool

Also, x−4Vt= Volume of the pool

⇒(x+5V+xV)t=x−4Vt⇒x+51+x1=x−41

⇒(2x+5)(x−4)=x2+5x⇒x2−8x−20=0⇒x2−10x+2x−20=0⇒(x−10)(x+2)=0

⇒x

Answer 2

check the attachment

answer 4 5 and 9 hrs