Physics, asked by MasterMatrix007, 1 month ago

A swimming pool is filled with water to a height of 5m. A) what is the pressure exerted by the water on the bottom of the pool B) if a small boy swims horizontally in the pool, calculate the pressure experienced by the body when he is at I) The surface ii) half depth iii) The bottom of the pool?​

Answers

Answered by spsk78
1

Information given

  • A swimming pool is filled with water to a height of 5m.

Questions Asked

A) what is the pressure exerted by the water on the bottom of the pool B) if a small boy swims horizontally in the pool, calculate the pressure experienced by the body when he is at I) The surface ii) half depth iii) The bottom of the pool

Formula going to be used

P = hpg

H = height

p = density of water

g = acceleration due to gravity

Known

density of water is 10³kg/m³ or 1g/cm³

Solution

Question 1

h = 5m

p = 10³kg/m³

g = 9.8

Now use the formula

P = hpg

P = 5×10³×9.8

P = 49×10³ Pa or 49000Pa

2nd Question

The pressure experienced on the body is = to his weight .

This is due to upthrust

3rd Question

The pressure exerted on him is equal to the weight off the displaced liquid.

For the above this is the force exerted by Upthrust

2nd Question

h = 2.5m

p = 10³kg/m³

g = 9.8 m /s²

Therefore

Using

P = hpg

P = 2.5×10³×9.8

P = 24.5 × 10³ Pa

For Question 3

h = 5m

p = 10³ kg/m³

g = 9.8 m/s²

Using

P = hpg

P = 5×10³×9.8

P = 49 × 10³ Pa

Answered by adventureisland
1

The pressure experienced by the body when he is at 49050\frac{N}{m^{2}}.

Explanation:

A) h=5m,g=9.81,density=1000\frac{kg}{m^{2}}

pressure=height*gravity*density

P=5*9.81*1000

=49050\frac{N}{m^{2}}

B)

(1).In this analysis the fluid does not exert any pressure on the boy. Instead, the boy's exerting pressure on  the fluid.

(2).half depth.

h=\frac{5}{2} =2.5m

P=2.5*9.81*1000

=24525\frac{N}{m^{2}}

(3). bottom of the bool

it be same pressure exerted  by the water on the bottom of the pool=49050\frac{N}{m^{2}}.

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