Question

A swimming pool is to be made with the walls having blue tiles and the floor having white tiles. the breadth, length and depth of the pool are 4m, 8m, 2m respectively. find the number of blue and white tiles required if they cover a surface area of 1.5sq m and 2 sq m respectively ​

Answer 1

LSA of the pool = 2(l+b)h

2×(8 +4)2

=2(12)2

=48 m sq

no. of blue tiles required= 48/ 1.5

= 32 tiles

area of the floor = 4×8

=32

no. of white tiles required =32/2

=16 tiles

Answer 2

The number of Blue tiles and White tiles used in making swimming pool is 32 and 16 respectively.

Step-by-step explanation:

Given,

Length(l) = 8 m

Breadth(b) = 4 m

Depth(d) = 2 m

We have to find the number of blue tiles and number of white tiles.

Solution,

For blue tiles.

Since the swimming pool is to be made with the walls having blue tiles.

So we calculate the area of four walls.

$Area\ of\ four\ walls=2(l+b)\times d$

On putting the values, we get;

$Area\ of\ four\ walls=2(8+4)\times2=2\times12\times2=48\ m^2$

Since the blue tiles covers the area of 1.5 sq. m.

So, number of tiles can be calculated by dividing area of four walls by area  of 1 tile.

This can be framed in equation form as;

$Number\ of\ tiles=\frac{Area\ of\ four\ walls}{area\ of\ 1\ tile}$

$Number\ of\ tiles=\frac{48}{1.5} =32$

Hence The number of Blue tiles used in making swimming pool is 32.

For white tiles.

Since  the floor having white tiles.

So we calculate the area of floor.

$area\ of\ floor=l\times b$

On putting the values, we get;

$area\ of\ floor=8\times 4=32\ m^2$

Since the white tiles covers the area of 2 sq. m.

So, number of tiles can be calculated by dividing area of floor by area  of 1 tile.

This can be framed in equation form as;

$Number\ of\ tiles=\frac{Area\ of\ floor}{area\ of\ 1\ tile}$

$Number\ of\ tiles=\frac{32}{2} =16$

Hence The number of White tiles used in making swimming pool is 16.