Question

a swimming pool of width 8 metre and length 23metre is filled with water to a depth of 4metre . calculate pressure on the bottom of the pool due to water.(density of water =1000kg/m^3 and gravity =9.8m/s^2​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Pressure=39200\:pa}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline{\bold{Given:}}} \\ \tt: \implies Length,Width \: and \: Height = 23 \: m,\: 8 \:m \: and \: 4 \: m \\ \\ \tt: \implies Density \: of \: water = 1000 \: kg /{m}^{3} \\ \\ \red{\underline{\bold{To \: Find:}}} \\ \tt: \implies Pressure \: at \: the \: bottom(\rho) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Density = \frac{Mass}{Volume} \\ \\ \tt: \implies 1000 \times \frac{kg}{m^{3}}= \frac{Mass}{23 \times 8 \times 4 }\times \frac{1}{m^{3}} \\ \\ \tt: \implies 1000 \times 736 \times kg= Mass \\ \\ \tt: \implies Mass = 736000 \: kg \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Pressure = \frac{Force}{Area} \\ \\ \tt: \implies Pressure = \frac{mg}{23 \times 8} \\ \\ \tt: \implies Pressure = \frac{736000 \times 9.8}{184}\times \frac{kg\times m}{s^{2}\times m^{2}} \\ \\ \tt\circ\:\frac{kg\:m}{s^{2}}\times \frac{1}{m^{2}}=N/m^{2}=pascal\\ \\ \green{\tt: \implies Pressure =39200 \: pa}\\\\ \green{\tt\therefore Pressure\:at\:the\:bottom\:of\:pool\:is\:39200\:pascal}$

Answer 2

$\pink \bigstar \huge \bf question$

a swimming pool of width 8 metre and length 23metre is filled with water to a depth of 4metre . calculate pressure on the bottom of the pool due to water.(density of water =1000kg/m^3 and gravity =9.8m/s^2

$\bigstar \large\bf answer$

Volume of water : 8 x 23 x 4

Mass of water = density of water x volume

= 1000Kg/m3 x 736m^3

= 736000Kg

Force exerted by water on the bottom surface = mass of water

= 736000Kg x 9.8ms2

= 721280N

Pressure : Force/Area

= 7212800/184

= 39200 pa