A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. What is the pressure on the scale wall of the pool at the junction with the bottom of the pool in the previous problem?
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volume = 24*9*3 you get 648m^3 converting it into dm^3 we get 0.648 liters thus density of water is considered as 1 so we get 0.648 kg
0.648*9.8 we get 6.35 N dividing by area we get 6.35/216 we get 0.0293 in SI UNIT
0.648*9.8 we get 6.35 N dividing by area we get 6.35/216 we get 0.0293 in SI UNIT
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