Question

a swimming pool of width 9.0 M and length 24.0 M is filled with water to a depth of 3.0 M calculate pressure on the bottom of pool due to the water

Answer 1

First of all we will find the volume of cube

$9 \times 3 \times 24 = 648mcu$
We know that pressure in fluid = v*density*gravity
Taking the density of water 1000 kg/mcu
" " gravity =10newton =648*1000*10=6480000
Ans = 6480000 PA

Answer 2

Answer:P = d h g

? P = (1000 kg / m3

) (3.0 m) (9.8 m / s2

)

? P = 29400 kg m2 / m3

s2

To simplify the units we cancel one m term in the m2

term in the numerator and one m term in

the m3

term in the denominator to get

? P = 29400 kg m / s2

m2

We know that 1N = 1 kg m / s2

so we can write

? P = 29400 N / m2

= 29400 Pa

Explanation: