Question

A synthetic metal wire with molar mass

M = 6.02x10 kg / mol has a mass denisity through the cross-section of wire is uniform and only one conduction electron per 10 atoms of metal is available. If number of conduction electrons per unit volume of wire is Nx102. Find N​

Answer 1

Answer:

given  = M = 6.02x10 kg / mol

              atoms =  10 atoms

              V =  N X 10²

TO find = N =?

solution =

number of conduction  electrons per unit  volume is ,

N =  (atoms / mole) X ( moles / mass) X (mass / volume )/ 10⁶

N =  Na X 1/M X ρ X 1/10⁶

N = 6.02 X 10²³ X 9 X 10³/ 6.02 X 10⁻² X 10⁶

N = 9 X 10²²

N = 9

The value of N  is 9.