Question

a syringe has a volume of 10.0 cm3 at pressure of 1 atmosphere if you plug the end so that no gas can escape and push the plunger down what must be the final volume to change the pressure 3.5 atom​

Answer 1

we know, from ideal gas equation,

$\quad\bf{PV=nRT}$

here it is mentioned that the amount of gas and the temperature remain constant, then ideal gas equation can simply be rewritten as: PV = k (constant )

i.e., $P_1V_1=P_2V_2$

given, $V_1=10cm^3,P_1=1atm$

and $P_2=3.5atm$

so, (10cm³) × (1atm) = $V_2$ × (3.5atm)

or, $V_2$ = 10/3.5 cm³

= 2.857cm³

hence, final volume = 2.857 cm³ to change the pressure 3.5 atm.

Answer 2

Answer:

hope it will help you

Explanation:

from ideal gas equation, TV is equal to an Aarti where TV is equal to constant therefore by using while of law P1 B1 is equal to P to Bitu therefore we 1 is equal to 10 centimetre cube is equal to 1 ATM Bitu is equal to 3.5 ATM cube into 1 ATM is equal to 2.5 cm is equal to 10 of 13.5 cm cube is equal to 2.85 CM cm cube therefore final volume is equal to 2.857 cm cube to change the pressure 3.5 ATM