Question

A system absorbs 300 calorie of heat with the result of that the volume of the system becomes double of its initial volume and temperature changes from 273 k to 546 k. The work done by the system on the surrounding is 200 calorie. Calculate delta e

Answer 1

According to the thermodynamic first law, The energy can neither be created nor destroyed but can be transformed from one form to the other form. Change in internal energy of a system is related to its heat and work done as follows.

ΔE=Q+W

where

ΔE is change in internal energy of the system.

Q IS Heat absorbed by the system=+300 cal∵

W is the work done by the system on the surroundings=-200 cal.

Calculating the change in internal energy of the system from heat and work done using the equation

ΔE=Q+W

ΔE=300 cal+(-200 cal)

ΔE=100 cal.

Therefore the change in internal energy of the system is 100 cal.

Answer 2

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