Question

a system absorbs 6kj of heat and does 1.5kj of work on its surrounding .the change in internal energy is

Answer 1

Use first law of thermodynamics

∆q = 6kJ

W = -1.5kJ (work is done by system so negative)

∆q + W = ∆U

∆U = 4.5kJ

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Answer 2

Use first law of thermodynamics

∆q = 6kJ

W = +1.5kJ (work is done on its surrounding so positive)

∆q + W = ∆U

∆U = +7.5kJ

Mark my answer as BRAINLIEST please !!!