Question

a system consisting of two masses connected by a massless rod lies along the x-axis is 0.2 kg mass is at a distance x equal to 0.5 m while 0.3 kg mass is at a distance x equal to 1 then the X co-ordinate of the centre of the mass will be

Answer 1

centre of mass position = μ = (massof first particle*distance+mass of second particle*distance)/total mass

$(0.2 \times 0.5 + 0.3 \times 1) \div (0.2 + 0.3)$
μ=0.4/0.5 =0.8m