a system consists of 6 identical particles each of mass m located on the vertices of a regular hexagon of side length a .the gravitational field at the centre of hexagon is?
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Hey friend,
Please refer to the attachment.
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Hey,
Explanation:
The center of mass of the original arrangement (six equal masses #m# on the six corners of a regular hexagon) is at the center of the hexagon.
The new arrangement (after two of the adjacent masses are doubled) is equivalent to the older one, with the addition of two masses equal to #m# masses added to two adjacent corners of the hexagon.
As far as the center of mass is concerned, this is equivalent to a mass of #6m# at the center of the hexagon
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