Question

a system does 5J of work amd releases 20J of heat to surrounding. the change in internal energy of the system is​

Answer 1

Answer:

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Answer 2

Answer:

Solution:- (C) −10J

As the heat is given to the system and work is done by the system, therefore,

q=+10J

W=−20J

Now from the first law of thermodynamics,

ΔU=q+W

⇒ΔU=10+(−20)=−10J

Hence the change in internal enrgy is −10J.