Question

A system gives out 30 J of heat and does 76 J of work. What is the internal energy change?​

Answer 1

Answer:

ΔU = q + w

ΔU = − 30 − 75 = − 105J

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Hope it helps you!!

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Answer 2

Hey there!

∆Q = - 30 J [heat released]

∆W = -76 j [ work done by the system]

Now as you know :

∆U = ∆Q + ∆W

∆U = -30 + (- 76)

∆U = (-106) J

Hence the change in internal energy is -106 joules.

Hope it helps! :)