Question

A system has three components in parallel with reliabilities 0.9 0.7 and 0.5. System reliability is

Answer 1

Answer:

Step-by-step explanation:

let the three component reliabilities be as R1=0.9, R2=0.7, R3=0.5

SYSTEM RELIABILITY, R= 1 - (1-R1)(1-R2)(1-R3)

R= 1 - (1-0.9)(1-0.7)(1-0.5)

R= 1 - (0.1)(0.3)(0.5)

R = 1 - 0.015

R = 0.985

Answer 2

The value of system reliability is 0.985.

Step-by-step explanation:

Given,

$R_{1}=0.9$, $R_{2}=0.7$ and $R_{3}=0.5$

To find, the value of system reliability, R = ?

We know that,

The system reliability, R

$=1-(1-R_{1})(1-R_{2})(1-R_{3})$

$=1-(1-0.9)(1-0.7)(1-0.5)$

$= 1-(0.1)(0.3)(0.5)$

$= 1-(0.03)(0.5)$

$=1-0.015$

$=0.985$

The value of system reliability = 0.985

Hence, the value of system reliability is 0.985.