Physics, asked by mitrajit1184, 9 months ago

A system is taken from state a to state c by two paths adc
and abc as shown in the figure. The internal energy at a is
Uᵃ = 10 J. Along the path adc the amount of heat absorbed
δQ₁ = 50 J and the work done δW₁ = 20 J whereas along the
path abc the heat absorbed δQ₂ = 36 J. The amount of work
done along the path abc is [NEET Kar. 2013]
(a) 6 J (b) 10 J
(c) 12 J (d) 36 J

Answers

Answered by tanujyadav28
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sai200147

sai200147

02.12.2019

Physics

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Answered

39 A system is taken from state a to state c by two

paths adc and abc as shown in the figure. The

internal energy at a is U = 10 J. Along the path

adc the amount of heat absorbed 8Q, = 50 J and

the work obtained SW, = 20 J whereas along the

path abc the heat absorbed SQ, = 36 J. The

amount of work along the path abc is

44.

45.

(1) 6J

(2) 10 J

(4) 36 J

(3) 12 J

2

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Answers

Fatimakincsem Expert

The amount of work along the path abc is 6 J.

Explanation:

According to first law of thermodynamics,

δQ = δU+δW

Along the path adc Change in internal energy,

δU1 = δQ1 - δW1

= 50 J - 20 J = 30 J

Along the path abc Change in internal energy,

δU2 = δQ2 - δW2; δU2 = 36 J - δW2

As change in internal energy is path independent

δU1 = δU2 => 30 J = 36 J - δW2

δW2 = 36 J - 30 J = 6 J

Thus the amount of work along the path abc is 6 J.

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