A system is taken from state a to state c by two paths adc
and abc as shown in the figure. The internal energy at a is
Uᵃ = 10 J. Along the path adc the amount of heat absorbed
δQ₁ = 50 J and the work done δW₁ = 20 J whereas along the
path abc the heat absorbed δQ₂ = 36 J. The amount of work
done along the path abc is [NEET Kar. 2013]
(a) 6 J (b) 10 J
(c) 12 J (d) 36 J
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sai200147
sai200147
02.12.2019
Physics
Secondary School
+5 pts
Answered
39 A system is taken from state a to state c by two
paths adc and abc as shown in the figure. The
internal energy at a is U = 10 J. Along the path
adc the amount of heat absorbed 8Q, = 50 J and
the work obtained SW, = 20 J whereas along the
path abc the heat absorbed SQ, = 36 J. The
amount of work along the path abc is
44.
45.
(1) 6J
(2) 10 J
(4) 36 J
(3) 12 J
2
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Answers
Fatimakincsem Expert
The amount of work along the path abc is 6 J.
Explanation:
According to first law of thermodynamics,
δQ = δU+δW
Along the path adc Change in internal energy,
δU1 = δQ1 - δW1
= 50 J - 20 J = 30 J
Along the path abc Change in internal energy,
δU2 = δQ2 - δW2; δU2 = 36 J - δW2
As change in internal energy is path independent
δU1 = δU2 => 30 J = 36 J - δW2
δW2 = 36 J - 30 J = 6 J
Thus the amount of work along the path abc is 6 J.
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