Question

A system of 5kg and 10kg blocks is shown in figure and strings and pulley are ideal. If 10kg block goes
down by 10m then find work done by tension on 5kg block.

Answer 1

Answer:

We know that,

acceleration (a) = Force (F)/mass(m)

Let's assume that 10kg block is moving downwards direction.

On 5kg Block :-

T - mg = ma

T - 5(10) = 5a

T - 50 = 5a........(1)

On 10kg Block :-

mg - T = ma

10(10) - T = 10a

100 - T = 10a.........(2)

From (1) and (2) :-

T - 50 = 5a..(1)

100 - T = 10a..(2)

On adding both these equation we get,

50 = 15a

a = 50/15

a = 10/3m/s²

So, acceleration is 10/3 m/s²

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Answer 2

Answer:

We know that,

acceleration (a) = Force (F)/mass(m)

Let's assume that 10kg block is moving downwards direction.

On 5kg Block :-

T - mg = ma

T - 5(10) = 5a

T - 50 = 5a........(1)

On 10kg Block :-

mg - T = ma

10(10) - T = 10a

100 - T = 10a.........(2)

From (1) and (2) :-

T - 50 = 5a..(1)

100 - T = 10a..(2)

On adding both these equation we get,

50 = 15a

a = 50/15

a = 10/3m/s²

So, acceleration is 10/3 m/s²

please please mark my answer as brainliest answer.

Explanation: