Question

A system of pulleys is used to lift a load of 1000 kgwt.
If the efficiency of the pulley system is 80% and
velocity ratio is 20, find the effort required to lift the
load.​
Explain​

Answer 1

Explanation:

(a) rα ˃ rd ˃ rp (b) rα= rp˂ rd `` (c) rα= rd ˃ rd (d) rα=

Answer 2

Answer:

Effort = 62.5 kg wt

Explanation:

Load = 1000 kg.wt

η = 80%

Velocity Ratio = 20

We know that,

η = M.A/V.R

0.8 = M.A/20

⇒ M.A = 16

Now,

Effort = Load/M.A

⇒ 1000/16

⇒ 62.5

Therefore,

Effort = 62.5 kg wt

Hope it helps!