Question

a system release 125 kJ of heat whole 104 kJ of work is done on tje system.calculate the change in internal energy(plz solve with steps)​

Answer 1

Answer:we know that,

∆U=q+w

q=heat energy

W=work done by the particle

Here, q=-125kj

W=104kj

∆U=-125+104

∆U=-21kj

Explanation:

Hope it helps