Question

A system releases 125 kJ of heat while 104 kJ of work is done on the system.

Calculate the change in internal energy.​

Answer 1

Answer:

By substraction the amount of heat and work done,

125kJ-104kJ= 21kJ

Answer 2

Answer:

Change in internal enery is 21kJ

Explanation:

Given:- Q = 125kJ , W = 104kJ

★From first law of thermodynamics

∆U = Q-W

∴ ΔU = 125kj - 104kj

ΔU = 21kJ Answer

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