Question

a system that consist of input and output​

Answer 1

Let c.p of one be x

The c.p of other be. y

S.p of first=x(120/100)=6x/5

S.p of other=y(80/100)=4y/5

Total c.p=x+y

Total s.p=(6x+4y)/5

6x/5=4y/5 (given)=3x=2y

Now c.p=x+3x/2=5x/2

S.p=(6x+6x)/5=12x/5

Loss=c.p-s.p=20 (given)

5x/2-12x/5=20

X/10=20

X=₹200

Y=(3/2)200=₹300