Question

a(t)=5t^2+3t. Find V at t=3sec.




Please give the solution of this problem.​

Answer 1

[tex]given \\ a(t) = 5 {t}^{2} + 3t \\ differentiating \: with \: respect \\ to \: t \: we \: get \\ \frac{da(t)}{dt} = 10t + 3 \\ now \: put \: t = 3 \\ \frac{da(t)}{dt} = 10 \times 3 + 3 = 33m/s[text]

Answer 2

Answer:

Answer in the attachment

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