Question

A table coaster in the shape of a rhombus has
diagonals of lengths 10 cm and 24 cm. Find the
length of each side of the coaster.

how did you got 5 from when finding the hypotenuse​

Answer 1

Answer:

Step-by-step explanation:

Let ABCD be the rhombus where, AC=10cm and BD=24cm

Let AC and BD intersect each other at O.Now, diagonals of rhombus bisect each other at right angles.

Thus, we have

AO=  

2

1

​  

×AC=  

2

1

​  

×10=5cm and  

BO=  

2

1

​  

×BD=  

2

1

​  

×24=12cm

In right angled △AOB,

⇒  (AB)  

2

=(AO)  

2

+(BO)  

2

 

⇒  (AB)  

2

=(5)  

2

+(12)  

2

 

⇒  (AB)  

2

=25+144

⇒  (AB)  

2

=169

∴  AB=13cm

∴  The length of each side of rhombus is 13cm.

Answer 2

Answer:

mark me brainliest

Step-by-step explanation:

As we know that the diagonals of a rhombus bisect each other.

So, the half diagonals would be 5 and 12

Let x be the side of the rhombus

And now if we apply the Pythagoras theorem then we get

$5^2+12^2=x^2\\25+144=x^2\\169=x^2\\\sqrt{169}=x\\13=x$

Hope this helps you:)