Question

A TABLE COASTER IN THE SHAPE OF RHOMBUS HAS DIAGONALS OF LENGTH 10CM AND 24CM .FIND THE LENGTH OF EACH SIDE​

Answer 1

$\huge\star\underline\mathcal\orange{ANSWER}$

Let ABCD be the rhombus where AC = 10cm and BD= 24 cm

Let AC and BD intersect each other at O.

Now, diagonals of rhombus bisect each other at right angles.

Thus, we have

AS= 1/2×AC = 1/2 ×10= 5cm

and

BD= 1/2×BD= 1/2 ×24=12cm

Since, AOB is a right angled ∆ , by Pythagoras theorem, we have

AB^2= AO^2 + BO^2

= AB^2 = 5^2 +12^2

= 25+144

= 169

Hence, AB = 13 cm