A table cover 4 m x 2 m is spread on a table. Find the cost of polishing the top of the table at rupee 2.25 per sq. m , if 25 cm table cover is hanging all around the table
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Answer: rupees 17.8593
Step-by-step explanation:
Total area of cloth = 2m × 4m = 8 m^2
=80000cm^2
area of cloth hanging = 25cm ×25 cm= 625cm^2
hence , area of table = Total area of cloth - area of cloth hanging
=>80000cm^2-625cm^2 =79375cm^2
= 7.9375 m^2
if 1m^2 costs rupees 2.25
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• • 7.9375 m^2 will cost rupees 17.8593
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