a table cover 4m*2 m is spared on a meeting table.if25cm of the table cover is hanging all around the table,then find the cost of polishing the table top at₹2.25 per square metre.
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Length of Cover (L)= 4m
Breadth of cover (B)=2 m
part of table cover hanging = 25cm =.25m
L" of the top(part cover on table)=
=4- (2×.25)=3.5cm
B" .............................................= 2-(2×.25)= 1.5cm
Area of part of the cover on the table = L"×B"
= 3.5 ×1.5 = 5.25 m^2
Cost of Polishing of table top =5.25 ×2.25
= 11.8125 Rs.
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Breadth of cover (B)=2 m
part of table cover hanging = 25cm =.25m
L" of the top(part cover on table)=
=4- (2×.25)=3.5cm
B" .............................................= 2-(2×.25)= 1.5cm
Area of part of the cover on the table = L"×B"
= 3.5 ×1.5 = 5.25 m^2
Cost of Polishing of table top =5.25 ×2.25
= 11.8125 Rs.
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