Question

A table cover 4m * 2m is spread on the table. If 25 cm of the table cover is hanging all around the table, find the area of the table top and the cost of polishing the table top at rs 25 per square metre

Answer 1

length of table cover = 4m = 400cm
breadth of table cover = 2m = 200cm
25cm of the cover is hanging all around
therefore, length of table = 400-25-25 = 350cm
breadth of table = 200-25-25 = 150cm

area of table top = area of rectangle
= l × b = 350 × 150 = 5250 cm2

cost of polishing = 25 × 5250/100 = 1312.5 rs

Answer 2

Question:

A table cover 4 m × 2 m is spread on a table. If 25 cm of the table cover is hanging all around the table, find the area of the table top and the cost of polishing the table top at Rs. 25 per square meter.

Answer:

${\mathsf{Given\::-}}$Table cover of dimensions 4 m × 2 m

• Length of the cover (l) = 4 m and
• Breadth of the cover (b) = 2 m

We have, 1 m = 100 cm

⇒ l = 400 cm and b = 200 cm

But, 25 cm of the cover is hanging from the table on all the four sides.

• Length of the table = (l – 25 – 25) cm
• = (400 – 25 – 25) cm

∴ Length of the table = 350 cm = 3.5 m

Similarly, Breadth of the table = (200 – 25 – 25) cm

∴ Breadth of the table = 150 cm = 1.5 m

${\bf{\blue{We\: know,\: area \:of \:a \:rectangle\: =\: length\: × \:breadth}}}$

⇒ Area of table top = 3.5 × 1.5

∴ Area of table top = 5.25 m2

It is given that the cost for polishing 1 m2 carpet is Rs. 25.

⇒ Cost of polishing the table = Rs. 25 × 5.25

∴ Cost of polishing = Rs. 131.25

Thus, the area of the table top is 5.25 m2, and the cost of polishing it is Rs. 131.25.

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