a table cover of dimension 3.5 m by 2.5 m is spread on a table . if 25 cm of the table cover , is hanging all around the table , find the area of the table cover , which is hanging out side the top of the table . find the cost of polishing the table top at rupees 20 per square metre?
Answers
2.75m²
Step-by-step explanation:
Area of table cover = (3.5*2.5)m²= 8.75m²
Length of table = 3.5 m - (25+25)cm = 3m
Breadth of table = 2.5 m - (25+25)cm= 2m
Area of table = 3m * 2m = 6m²
Area of table cover hanging out of the table = area of cover - area of table
Area of table cover hanging out of the table = 8.75m²-6m² = 2.75m² ans.
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Step-by-step explanation:
Asta of table cover = length×breadth
= 3.5×2.5=8.75m²
8.75m²Length of table =3.5m-[25×2cm]
=3.5-[50cm]
=3.5-0.5
=3
=3Breadth of table = 2.5m - [25x2 cm]
=3Breadth of table = 2.5m - [25x2 cm]= 2.5m-[50 cm]
=3Breadth of table = 2.5m - [25x2 cm]= 2.5m-[50 cm]=25m-0.5 m.
5 m.= 2 cm
5 m.= 2 cmArea of table = 3x 2=6m²
Area of table cover hanging =8.75-6 = 2.75m²
Polishing cost of 1m²=₹20
Polishing cost of 2.75m²=2.75×20=₹120
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