A table cover of dimensions 3.5m by 2.5m is spread on a table. If 25 cm of the table cover, is hanging all around the table, find the area of the table cover, which is hanging outside the top of the table. Find the cost of polishing the tabletop at Rupees 20per square meter
Answers
The area of the table cover, which is hanging outside the top of the table is 2.75 m². The cost of polishing the tabletop at Rupees 20 per square meter is Rs. 55.
Step-by-step explanation:
Step 1:
The dimensions of the table cover are given as,
Length = 3.5 m
Breadth = 2.5 m
∴ The area of the table cover = Length * Breadth = 3.5 * 2.5 = 8.75 m²
Step 2:
Also, the part of the table cover which is hanging all around the table is 25 cm i.e., the width = 25 cm = 0.25 m
So, the dimensions of the tabletop will be,
length = 3.5 – (2*0.25) = 3 m
breadth = 2.5 – (2*0.25) = 2 m
∴ The area of the table top = length * breadth = 3 * 2 = 6 m²
Thus,
The area of the table cover, which is hanging outside the top of the table is,
= [The area of the table cover] – [The area of the table top]
= 8.75 – 6
= 2.75 m²
Step 3:
The cost of polishing the tabletop per square meter is given as Rs. 20.
Thus,
The total cost of polishing the table top will be
= Rs. 20 × 2.75 m²
= Rs. 55
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Step-by-step explanation:
3.5*2.5=8.75 m sq
25cm =0.25m
3.5-2*0.25=3
2.5-2*0.25=2
3*2=6
8.75-6=2.75
2.75*20=₹55
2.75sq , ₹55
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