A table has an equilateral triangular hole, each of which has a length of 4√3 cm, on which a 10 cm radius ball is placed. What part of the vertical diameter of the ball will be on the table?
Answers
Answered by
1
Answer:
20cm
Step-by-step explanation:
because the radius is 10cm
double of the radius is diameter
so, 2×radius
=2×10
=20cm
Similar questions