a table has its minute hand 4.0 cm long average velocity of the tip of the minute hand between 6:00 a.m. to 6:30 a.m. and 6:00 a.m. to 6:30 p.m. will be respectively be
Answers
Answer:
AVERAGE SPEED = 4.4 × 10-³ cm/s
AVERAGE VELOCITY = 1.8 × 10-⁴ cm/s
Step-by-step explanation:
given that,
the length of the minute hand = 4 cm
from 6:00 am to 6:30 am
the minute hand will cone just opposite to the earlier position.
We know that,
Average velocity = displacement/time
here,
displacement = 2 × 4 = 8 cm
given time,
= 30 minutes
= 30 × 60 seconds
= 1800 seconds
Average velocity = 8/1800
= 44.444 × 10-⁴
= 4.4 × 10-³ cm/s
now,
from 6:00 am to 6:30 pm
displacement will same
and time = 12 hours + 30 minutes
= 12(3600) + 30(60) seconds
= 43200 + 1800
= 45000 seconds,
Average velocity = 8/45000
= 0.0001777
= 0.000178
= 1.78 × 10-⁴ cm/s
so,
_______________
AVERAGE SPEED
= 4.4 × 10-³cm/s
AVERAGE VELOCITY
= 1.8 × 10-⁴ cm
HeRe Is Your Ans ⤵
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Ans :-
➡Average Speed = 0.00698 cm/s
➡Average Velocity = 0.0044 cm/s
Average velocity and average speed between 6 am to 6:30 pm is same as that of 6 am to 6:30 am
Given :-
➡Length Of Minute Hand = 4.0 Cm
To Find :-
➡Average Speed = ?
➡Average Velocity = ?
Solution :-
Between 6 am to 6:30 am
➡Average speed = Total distance ÷ Time
➡πr ÷ (30 × 60 seconds)
➡4π ÷ 1800
➡0.00698 cm/s
➡Average velocity = Total displacement ÷ Time
➡2r ÷ (30 × 60 seconds)
➡8 ÷ 1800
➡ 0.0044 cm/s
Average velocity and average speed between 6 am to 6:30 pm is same as that of 6 am to 6:30 am
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