A table has three drawers. It is known that one of the drawers
contains two silver coins, another contains two gold coins and the
third one contains a silver coin and a gold coin. One of the drawers
is opened at random and a coin is drawn. It is found to be a silver
coin. What is the probability that the other coin in the drawer is a
gold coin ?
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Answer:
first box prob +second box prob+third box prob (gold coins it is )
0+1+1/2=3/2
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