Question

A table top is 9dm 5cm long 6dm 5cm broad.what will be the cost to Polish it at the rate of 20 pàise per square centimetres

Answer 1

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Answer 2

Cost to Polish the table is ₹1235.

Step-by-step explanation:

Given:

Length of the table = 9 dm 5 cm.

Since length is in dm we will convert in cm.

Now we know that;

1 dm = 10 cm

so 9 dm = 90 cm

So the length will become;

Length of the table = $90\ cm+ 5\ cm=95\ cm$

Also Given:

Breadth of the table = 6dm 5cm

1 dm = 10 cm

so 6 dm = 60 cm

Breadth of the table = $60\ cm+ 5\ cm=65\ cm$

Now we know that;

Since table are in rectangular form;

So Area of table will be equal to length times breadth.

framing in equation form we get;

Area of table $95\times 65 = 6175\ cm^2$

Now Given:

Cost to Polish per square centimeter = 20 paise

So to Polish 6175 square centimeter =  Cost to Polish 6175 square centimeter

By Using Unitary method we get;

Cost to Polish 6175 square centimeter = $20\times 6175 = 123500\ paise$

Now 100 paise = ₹1

So 123500 paise = $\frac{123500}{100} =1235\ rupees$

Hence Cost to Polish the table is ₹1235.