Question

A table top is 9dm 5cm long 6dm 5cm broad.what will be the cost to Polish it at the rate of 20 pàise per square centimetres



PLZ WRITE THE ANSWER STEP BY STEP​

Answer 1

Answer:

Cost is Rs.1,23,500

Step-by-step explanation:

table top

Length     =9dm5cm

               = 9*10+5cm                    [1 dm=10cm thus 9dm is 90cm]

               =95cm    

Breadth= 6dm5cm

             =60+5cm

              =65 cm

AREA OF RECTANGLE= L*B

                                       =95*65 sq.cm

                                        =6175 sq.cm

Rate = 20 paise per sq.cm

Cost=rate*area

       = 6175*20

       = Rs.1,23,500

Answer 2

Answer:

6400 rupees  is the cost of polishing

Step-by-step explanation:

In context to the question it is asked to find the cost to polish at the rate of 20 paisa per square centimetre

Data is given as follows

L = 9 d m  5 cm

B = 6 d m 5 cm

As in question it is asked to find the answer in cm

So first converting all the value which is in d m into cm

d m means decimetre

As 1 d m =10 cm

so

9 d m = 90 cm

6 d m = 60 cm

Now

L =90 d m 5 cm

=95 cm

and

B= 6 d m 5

cm=65 cm

Now table top is nothing but rectangle

So putting the value of L and B in formula

perimeter of rectangular top

$P=2(L+B)$

$P=2(95+65)\\P=2(160)\\P=320cm^{2}$

This is the perimeter of table top  which is polished  at the rate 20 paise per square centimetre

so cost for polishing table top= 320 x 20

                                                        =6400 rupees