Question

A table was sold at 20 %(percentage) loss at rupees 800 , then find the CP of the table?​

Answer 1

Given :

• Selling Price = ₹800
• Loss% = 20%

To Find :

• Cost Price = ?

Solution :

~We know that,

$\bf \longrightarrow \green{\boxed{ \pink{\bf C.P. = \frac{100}{100 - Loss\%} \times S.P.}}} \: \purple\bigstar$

Substituting the values,

$\longrightarrow \displaystyle{{{\sf C.P. = \frac{100}{100 - 20\%} \times 800}}} \\ \\ \longrightarrow \displaystyle{{{\sf C.P. = \frac{100}{100 - 20} \times 800}}} \\ \\ \longrightarrow \displaystyle{{{\sf C.P. = \frac{100}{80} \times 800}}} \\ \\ \longrightarrow \displaystyle{{{\sf C.P. = \frac{100}{8 \cancel0} \times 80 \cancel0}}} \\ \\ \longrightarrow \displaystyle{{{\sf C.P. = \frac{100}{ \cancel8} \times \cancel{80} { \: }^{10} }}} \\ \\ \longrightarrow \displaystyle{{{\sf C.P. = 100 \times 10}}} \\ \\ \longrightarrow \displaystyle{{{ \boxed{ \red{\bf C.P. = Rs. \: 1000}}}}} \: \green\bigstar$

Hence, Cost Price is ₹1000.

Answer 2

Answer:

Cost price is ₹1000 Hope it helps u mark me brainlest