Math, asked by vilasjadhav, 1 year ago

a table was sold for $900 at a loss of 25%.if the same table was sold for$950.what would have been the profit or loss percent?

Answers

Answered by Anonymous
28
Solutions :-


Given :

Selling price of table = $ 900
Loss = 25%


Find the cost price of table :-

C.P = (S.P × 100)/(100 - loss)
= $ (900 × 100)/(100 - 25)
= $ 90000/75
= $ 1200


Now, we have

Cost Price = $ 1200
Selling price = $ 950


Cost Price is greater than the Cost price. Therefore, Loss.


Loss = C.P - S.P
= $ (1200 - 950)
= $ 250


Loss % = (loss × 100)/C.P %
= (250 × 100)/1200 %
= 25000/1200 %
= 20.83 % approx.



Hence,
Loss percent = 20.83%
Answered by SmãrtyMohït
43

Here is your solution

Given :-

A table was sold for $900


I. e

Selling price of table = $ 900

Loss = 25%

To Find the cost price of table :-

we know that

C.P = (S.P × 100)/(100 - loss)

=> ($900 × 100)/(100 - 25)

=> $90000/75

=> $ 1200

The Cost Price is $ 1200.

Given:-

Selling price is $ 950

Hence,

Cost Price is greater than the Cost price. Therefore,

it is Loss.


Loss = C.P - S.P

=> ($1200 - $950)

=> $250


Now loss%

Loss % = (loss × 100)/C.P %

=> (250 × 100)/1200 %

=> 25000/1200 %

=> 20.83 % (approx.)

Hence,

The Loss percent is 20.83%

Hope it helps you .


SmãrtyMohït: thanks
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