a table was sold for $900 at a loss of 25%.if the same table was sold for$950.what would have been the profit or loss percent?
Answers
Answered by
28
Solutions :-
Given :
Selling price of table = $ 900
Loss = 25%
Find the cost price of table :-
C.P = (S.P × 100)/(100 - loss)
= $ (900 × 100)/(100 - 25)
= $ 90000/75
= $ 1200
Now, we have
Cost Price = $ 1200
Selling price = $ 950
Cost Price is greater than the Cost price. Therefore, Loss.
Loss = C.P - S.P
= $ (1200 - 950)
= $ 250
Loss % = (loss × 100)/C.P %
= (250 × 100)/1200 %
= 25000/1200 %
= 20.83 % approx.
Hence,
Loss percent = 20.83%
Given :
Selling price of table = $ 900
Loss = 25%
Find the cost price of table :-
C.P = (S.P × 100)/(100 - loss)
= $ (900 × 100)/(100 - 25)
= $ 90000/75
= $ 1200
Now, we have
Cost Price = $ 1200
Selling price = $ 950
Cost Price is greater than the Cost price. Therefore, Loss.
Loss = C.P - S.P
= $ (1200 - 950)
= $ 250
Loss % = (loss × 100)/C.P %
= (250 × 100)/1200 %
= 25000/1200 %
= 20.83 % approx.
Hence,
Loss percent = 20.83%
Answered by
43
Here is your solution
Given :-
A table was sold for $900
I. e
Selling price of table = $ 900
Loss = 25%
To Find the cost price of table :-
we know that
C.P = (S.P × 100)/(100 - loss)
=> ($900 × 100)/(100 - 25)
=> $90000/75
=> $ 1200
The Cost Price is $ 1200.
Given:-
Selling price is $ 950
Hence,
Cost Price is greater than the Cost price. Therefore,
it is Loss.
Loss = C.P - S.P
=> ($1200 - $950)
=> $250
Now loss%
Loss % = (loss × 100)/C.P %
=> (250 × 100)/1200 %
=> 25000/1200 %
=> 20.83 % (approx.)
Hence,
The Loss percent is 20.83%
Hope it helps you .
SmãrtyMohït:
thanks
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