A tailor needs at least 40 large buttons and 60 small buttons. In the market two kinds of boxes are available. Box A contains 6 large and 2 small buttons and costs 3, box B contains 2 large and 4 small buttons and costs 2. Find out how many boxes of each type should be purchased to minimize the expenditure.
Answers
Answer:
The tailor should buy 2 boxes of type A & 14 boxes of type B in order to minimize the expenditure.
Explanation:
The Box A contains Buttons = 6 Large and 2 Small
The Box B contains Buttons = 2 Large and 4 Small
We have to buy both these boxes in such a way that
x A + y B = 40 L + 60 Small
x( 6 L + 2 S) + y ( 2 L + 4 S) = 40 L + 60 S
6x L + 2x S + 2y L + 4y S = 40 L + 60 S
6x L + 2y L = 40 L AND 2x S + 4y S = 60 S
6x + 2y = 40 AND 2x + 4y = 60
Solving these, we get
x = 2 and y = 14
Cost of Box A = 3 Rupees
Cost of Box B = 2 Rupees
And we have to minimize the expenditure.
For x = 2 and y =14:
Total Cost = Cost of A boxes + Cost of B Boxes
= 2(3) + 14(2) = 34 Rupees
Answer:
34 Rupees
Step-by-step explanation: