Math, asked by Ambikarajawat6870, 1 year ago

A takes 10 days less than the time taken by B to finish a piece of work, if both A and B together finish a work in 12 days. Find the time taken by B to finish the work.

Answers

Answered by anu2720
4
Let A can finish the work in x days

B can finish the work in x+10 days

So the work done by A in one day = 1/x times the total work

and the work done by B in one day = 1/x+10 times the total work
In 12 days, then can do the work together

(12/x)+(12/x+10)=1

solve

x=20
Hence A complete the work in 20 days and B in 20+10 = 30 days

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let A takes x days then B take (x+10) days as given in question,

1/x + 1/(x+10) = 1/12

by solving this we get x= -6, 20

since days r not negative hence x=20

therefore work done by B=20+10=30

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