Question

A takes 3 hour more than B to walk 30 km. But if A doubles his pace, he is ahead of B by 3 /2 hours. Find their speed of walking

Answer 1

GIVEN :
Distance = 30 km

Let speed of A be = x km/h & speed of B be = y km/h

Time taken by A to cover 30 km = 30/x
[Time = Distance/Speed]

Time taken by B to cover 30 km = 30/y

30/x = 30/y + 3
30/x - 30/y = 3.............(1)
[Given : A takes 3 hour more than B to walk]

When A doubles his speed, then time taken by A = 30/2x
[Given : Time taken by B = Time taken by A + 3/2 hours]
30/y = 30/2x + 3/2
30/y - 30/2x = 3/2
30/y - 15/x = 3/2.............(2)

Let 1/x = p & 1/y = q

So eqn (1) becomes
30p - 30q = 3...............(3)

And eqn (2) becomes
30q - 15p = 3/2..............(4)

On adding equation 3 and 4

30p - 30q = 3
+ (-15p) + 30q = 3/2
_________________
15p = 9/2
p = 9/(2×15)
p = 3/10

On putting the value of p = 3/10 in equation 3
30p - 30q = 3
30(3/10) - 30q = 3
9 - 30q = 3
-30q = -6
q = 1/5

Now, 1/y = q
1/y = 1/5
y = 5km/h

&, 1/x = p
1/x = 3/10
x = 10/3 km/h

Hence
A = 10/3 km/h
B = 5 km/h

Be BRAINLY

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Given:

• Distance = 30 km

Let speed of A be = x km/h & speed of B be = y km/h

Time taken by A to cover 30 km = 30/x

[Time = Distance/Speed]

Time taken by B to cover 30 km = 30/y

30/x = 30/y + 3

30/x – 30/y = 3———–(i)

When A doubles his speed, then the time taken by A = 30/2x

30/y = 30/2x + 3/2

30/y – 30/2x = 3/2

30/y – 15/x = 3/2————–(ii)

Let us assume that 1/x = p & 1/y = q

So equation (i) and equation (ii) becomes

30p – 30q = 3——–(iii)

30q – 15p = 3/2——–(iv)

On adding equation (ii) and (iv) we get,

30p – 30q = 3

+ (-15p) + 30q = 3/2

_________________

15p = 9/2

p = 9/(2×15)

p = 3/10

Substituting the value of p = 3/10 in equation(iii) we get

30p – 30q = 3

30(3/10) – 30q = 3

9 – 30q = 3

-30q = -6

q = 1/5

Now we know that , 1/y = q

1/y = 1/5

y = 5km/h

&, 1/x = p

1/x = 3/10

x = 10/3 km/h

Hence:

• A = 10/3 km/h
• B = 5 km/h

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