Question

A takes 6 days less than B to do a work. If both A and B working together can do it in 4 days.
how many days will B take to finish it?
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Answer 1

Answer:

8

Step-by-step explanation:

6+2=8

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Answer 2

Answer:

B completes the work in 12 days

Step-by-step explanation:

Consider B takes x days

Then A takes x-6 days

If both A and B working together can do it in 4 days

$\frac{1}{A} +\frac{1}{B} = \frac{1}{4}\\\frac{1}{x-6} +\frac{1}{x} = \frac{1}{4}\\\frac{x+x-6}{x(x-6)} =\frac{1}{4} \\4(2x-6)=x^2-6x\\8x-24=x^2-6x\\x^2-14x+24=0$

by solving above equation

$x^2-12x-2x+24=0\\x(x-12)-2(x-12)=0\\(x-12)(x-2)=0\\x= 12\\x=2$

x =12 is the required days

So B completes the work in 12 days