A takes 6 days less than B to do work.if both A and B working together can do it in 4 days,how many days will B take to finish it
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Let A take x days then B will take x-6 days
gives that :
A's work + B's work =4 days
A's 1day's work +B's 1 day's work ,i.e., (1/x)+(1/x-6) = 1/4
(x-6+x)/x(x-6)= 1/4
(2x-6)4=x^2-6x
8x-24=x^2-6x
x^2-14x+24=0
x^2-12x-2x+24=0
x(x-12)-2(x-12)=0
(x-12)(x-2)=0
so, x = 12 or 2 but if x is 2 then x-6 ,i.e.,2-6 , is negative and no. of days cannot be negative so x will be 12
therefore, B will take (12-6),i.e., 6 days
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