Question

A takes 6 days less than the time taken by b to finish a piece of work. If both a and b together can finish it in 4 days, find the time that b would take to finish this work by himself

Answer 1

Answer:

Let the number of days taken by A to finish the work be x.

Let the number of days taken by A to finish the work be x.Then, number of days taken by B to finish the work = x + 6

Let the number of days taken by A to finish the work be x.Then, number of days taken by B to finish the work = x + 6Now, work done by A in one day = and work done by B in one day =

Let the number of days taken by A to finish the work be x.Then, number of days taken by B to finish the work = x + 6Now, work done by A in one day = and work done by B in one day = Now, we have:

Let the number of days taken by A to finish the work be x.Then, number of days taken by B to finish the work = x + 6Now, work done by A in one day = and work done by B in one day = Now, we have:x = 6 (neglecting x = -4)

Let the number of days taken by A to finish the work be x.Then, number of days taken by B to finish the work = x + 6Now, work done by A in one day = and work done by B in one day = Now, we have:x = 6 (neglecting x = -4)Thus, time taken by B to finish the work = x + 6 = 12 days

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