Question

A takes 6 days less than the time taken by B to finish a piece of work . If both A and Btogether can finish it in 4 days , then find the time taken by B to finish

Answer 1

Time taken by A is x
Time taken by B be y
x=y-6
x-y=-6
x+y=4
2x=-2
x=-1
-1+y=4
y=4+1
y=5
Therefore time taken by B is 5dsys

Answer 2

Answer:

no. of days taken by A to finish that work = x

then, no. of days taken by B to finish that work = x+6

now, work done by A in one day = 1/x and work done by B in one day = 1/x+6

now, work done by both A and B in one day,

1/x + 1/x+6 = 1/4

{(x+6)+x}/x(x+6) = 1/4

8x + 24 = x2 + 6x

x2-2x - 24 = 0

x2 -6x +4x -24 = 0

x(x-6) +4(x-6) = 0

(x+4) (x-6) = 0

so, x= 6  (neglecting x = -4)

so, time taken by B to finish the work = x+6 = 12 days