Question

A takes 6days less than B by to finish a piece of work. if both A and B together can finish the work in 4 days. find the time taken by B along the to finish the work.

Answer 1

Answer:

time taken alone by B = 12 Days

Step-by-step explanation:

Let us assume b takes alone x days

Then A takes x-6 days

1/4 = 1/x + 1/(x-6)

solving we get

x² - 14x + 24 = 0

(x-12)(x-2) = 0

x = 12    as x can not be 2 because then Number of Days for A will be -ve (2-6 = -4 )